32Improper integral of
Evaluate the improper integral .
Replace infinity with t, integrate, then let t go to infinity. Antiderivative is −1/x, so the integral is (1 − 1/t) → 1 as t→∞. The area is finite and equals 1.
Evaluate the improper integral .
Replace infinity with t, integrate, then let t go to infinity. Antiderivative is −1/x, so the integral is (1 − 1/t) → 1 as t→∞. The area is finite and equals 1.