39Modulus and argument of z
Find the modulus and the argument (in degrees) of z = 1 + √3 i.
The modulus |z| = 2 and the argument θ = 60°. Using |z| = √(a² + b²) = √(1² + (√3)²) = √4 = 2, and θ = tan⁻¹(√3/1) = 60° since the point lies in the first quadrant. Check: 2cos60° = 1 and 2sin60° = √3.