38Quadratic with complex roots
Solve .
The equation has no real solutions, only complex ones: x = -2 ± 3i. Using the quadratic formula with a=1, b=4, c=13 gives √(16-52) = √-36 = 6i, so x = (-4 ± 6i)/2 = -2 ± 3i. Checking x = -2+3i back into the equation gives 0.