silemus.

32Sum of infinite geometric series

Find the sum of the infinite series 12 + 8 + 16/3 + ….

The series converges to 36. It's geometric with a = 12 and r = 2/3 (since |r| < 1), so S = a/(1−r) = 12/(1/3) = 36. Check: 36·(1/3) = 12, the first term.

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