silemus.

26Remainder theorem

Find the remainder when 2x3−3x2+4x−5\displaystyle 2x^3 - 3x^2 + 4x - 5 is divided by x−2\displaystyle x - 2.

The remainder is 7. By the remainder theorem, dividing by x − 2 means the remainder equals P(2): 2(8) − 3(4) + 4(2) − 5 = 16 − 12 + 8 − 5 = 7, no long division needed.

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