25Solving a cubic by factoring
Solve .
The cubic factors as (x−1)(x−2)(x−3)=0, so the roots are x = 1, 2, 3. Finding x=1 works first lets you divide it out to a quadratic, which factors into (x−2)(x−3). Check: 8−24+22−6=0 for x=2.
Solve .
The cubic factors as (x−1)(x−2)(x−3)=0, so the roots are x = 1, 2, 3. Finding x=1 works first lets you divide it out to a quadratic, which factors into (x−2)(x−3). Check: 8−24+22−6=0 for x=2.