silemus.

23Solving 2^(x+1)=3^x

Solve 2x+1=3x\displaystyle 2^{x + 1} = 3^x. Give the answer to 4 decimal places.

The solution is x ≈ 1.7095. Taking ln of both sides turns the exponents into multipliers: (x+1)ln2 = x ln3, then collecting x terms gives x = ln2/(ln3−ln2) ≈ 0.6931/0.4055 ≈ 1.7095. Check: both 2^2.7095 and 3^1.7095 ≈ 6.541.

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