silemus.

19Angle in a semicircle

AB is a diameter of a circle and C is a point on the circle. ∠CAB = 34°. Find ∠CBA.

Angle CBA is 56°. Since AB is a diameter, angle ACB is 90° (angle in a semicircle), so the other two angles make up the remaining 90°: 180° − 90° − 34° = 56°.

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