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2Exterior angle of a triangle

In triangle ABC, side BC is extended past C to D. The exterior angle ∠ACD is 125° and ∠A = 58°. Find ∠B.

Angle B is 67°. The exterior angle ∠ACD equals the sum of the two remote interior angles, so 125 = 58 + ∠B, giving ∠B = 67°. Check: 58 + 67 + 55 = 180°, since ∠C = 180 − 125 = 55°.

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