silemus.

26Vertex of a parabola

Find the vertex of y=−2x2+8x−3\displaystyle y = -2x^2 + 8x - 3. Is it a maximum or a minimum?

The vertex is (2, 5), and since the coefficient of x² is negative (−2), the parabola opens downward, making it a maximum. Using x = −b/(2a) = −8/(−4) = 2, then y = −2(2)² + 8(2) − 3 = 5.

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