silemus.

4L'Hopital's rule, limit

Use L'Hôpital's rule to find lim⁡x→0ex−1−xx2\displaystyle \lim_{x\to 0} \frac{e^x - 1 - x}{x^2}.

Plugging in x=0 gives 0/0, so differentiate top and bottom: (eˣ−1)/2x, still 0/0, so differentiate again: eˣ/2, which gives 1/2. A Taylor series check (eˣ−1−x ≈ x²/2) confirms the limit is 1/2.

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