silemus.

30Integral of sin⁡2x\sin^2 x

Evaluate ∫0π/2sin⁡2x dx\displaystyle \int_0^{\pi/2} \sin^2 x\,dx. Give the answer to 3 decimal places.

Rewrite sin²x using the double angle identity (1−cos2x)/2, then integrate term by term. This gives π/4, which is about 0.785. Checked by noting sin²x averages to 1/2 over the interval, times the interval length π/2.

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