23Related rates, sphere volume
A spherical balloon's radius grows at 2 cm/s. How fast is its volume increasing when the radius is 5 cm? Give the answer to 3 decimal places.
Differentiate V = (4/3)πr³ with respect to time to get dV/dt = 4πr²(dr/dt), the chain rule since r depends on t. Plugging r = 5 and dr/dt = 2 gives dV/dt = 200π ≈ 628.319 cm³/s.