silemus.

6Limit of (1−cos⁡x)/x2(1 - \cos x)/x^2

Find lim⁡x→01−cos⁡xx2\displaystyle \lim_{x\to 0} \frac{1 - \cos x}{x^2}.

Use 1 − cos x = 2sin²(x/2) to remove the 0/0 form. Rewriting x² as 4(x/2)² turns the limit into (1/2)·(sin(x/2)/(x/2))², and since sinθ/θ → 1, the limit equals 1/2. Checking x = 0.1 gives ≈0.4996, close to 1/2.

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