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16Largest angle, law of cosines

A triangle has sides 5, 7 and 9. Find its largest angle in degrees. Give the answer to 3 decimal places.

The largest angle, opposite the side of length 9, is about 95.739°. Using cos B = (5²+7²−9²)/(2·5·7) = −0.1, then B = cos⁻¹(−0.1) ≈ 95.739°, checked by 25+49−70cos(95.739°) ≈ 81.

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