silemus.

26Interior angles of an octagon

Find the sum of the interior angles of an octagon, and the size of each interior angle of a regular octagon.

The interior angles of an octagon sum to 1080°, and each angle of a regular octagon is 135°. Using (n−2)×180° with n=8 gives (8−2)×180° = 1080°, then 1080°÷8 = 135° per angle. Check: 8×135° = 1080°.

How good is this answer?