silemus.

51Distance point to plane

Find the distance from the point (1,2,3)\displaystyle (1, 2, 3) to the plane x+2y+2z=0\displaystyle x + 2y + 2z = 0. Give the answer to 3 decimal places.

Use the point-to-plane formula: distance equals the plane's left side evaluated at the point, divided by the length of the normal vector (1,2,2). That's |1+4+6|/√9 = 11/3 ≈ 3.667.

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