silemus.

21Singular matrix, det=0

For which k\displaystyle k is A=[1k26]\displaystyle A = \begin{bmatrix}1 & k\\2 & 6\end{bmatrix} singular?

A matrix is singular when its determinant is 0. Here det(A) = 1·6 − k·2 = 6 − 2k, so setting 6 − 2k = 0 gives k = 3. Check: 6 − 2(3) = 0.

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