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11Eigenvalues of a triangular matrix

Find the eigenvalues of A=[210034005]\displaystyle A = \begin{bmatrix}2 & 1 & 0\\0 & 3 & 4\\0 & 0 & 5\end{bmatrix}.

Since A is upper triangular (zeros below the diagonal), its eigenvalues are just its diagonal entries: 2, 3, and 5. This follows because det(A−λI) for a triangular matrix is the product (2−λ)(3−λ)(5−λ), which is zero exactly at λ = 2, 3, 5.

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