silemus.

8Eigenvalues of a 2×22\times 2 matrix

Find the eigenvalues of A=[01−2−3]\displaystyle A = \begin{bmatrix}0 & 1\\-2 & -3\end{bmatrix}.

Eigenvalues solve det(A−λI)=0. For A = [[0,1],[−2,−3]], this gives λ²+3λ+2=0, which factors as (λ+1)(λ+2)=0, so λ = −1 and λ = −2. Check: their sum −3 matches the trace of A.

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