silemus.

7Eigenvalues of a 2×22\times 2 matrix

Find the eigenvalues of A=[2112]\displaystyle A = \begin{bmatrix}2 & 1\\1 & 2\end{bmatrix}.

Solve det(A − λI) = 0: for this matrix that gives (2−λ)² − 1 = 0, which simplifies to λ² − 4λ + 3 = 0, factoring as (λ−1)(λ−3) = 0. So the eigenvalues are λ = 1 and λ = 3, matching the trace check 1+3 = 2+2.

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