silemus.

6Eigenvalues of a 2×22\times 2 matrix

Find the eigenvalues of A=[4123]\displaystyle A = \begin{bmatrix}4 & 1\\2 & 3\end{bmatrix}.

Solve det(A − λI) = 0, which gives λ² − 7λ + 10 = 0. Factoring, (λ − 2)(λ − 5) = 0, so the eigenvalues are λ = 2 and λ = 5. Check: trace 4+3=7 matches 2+5=7.

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