4Determinant of a matrix
Find for . Is invertible?
Expanding along the top row: det A = 3(0−1) − 1(2−1) + 2(2−0) = −3 −1 +4 = 0. Since det A = 0, the matrix A is not invertible.
Find for . Is invertible?
Expanding along the top row: det A = 3(0−1) − 1(2−1) + 2(2−0) = −3 −1 +4 = 0. Since det A = 0, the matrix A is not invertible.