silemus.

48Double integral of x+yx + y

Evaluate ∫01∫02(x+y) dy dx\displaystyle \int_0^1 \int_0^2 (x + y)\,dy\,dx.

Work inside out: integrate x + y over y from 0 to 2 first, getting 2x + 2. Then integrate that over x from 0 to 1, giving 3. Checked by reversing the order of integration, same result, 3.

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