silemus.

20Inflection point of cubic

Find the x\displaystyle x-coordinate of the inflection point of f(x)=x3−6x2+5\displaystyle f(x) = x^3 - 6x^2 + 5.

An inflection point is where f''(x) changes sign. Here f''(x) = 6x − 12 = 0 gives x = 2, and f'' goes from −6 at x=1 to 6 at x=3, confirming the bend switches there. So x = 2.

How good is this answer?