silemus.

18Critical points of x3−3xx^3 - 3x

Find and classify the critical points of f(x)=x3−3x\displaystyle f(x) = x^3 - 3x.

Set f'(x) = 3x² − 3 = 0, giving critical points x = −1 and x = 1. The second derivative f''(x) = 6x is negative at x = −1 (local max, value 2) and positive at x = 1 (local min, value −2).

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