silemus.

14Chain rule, f(x)=(2x+1)5f(x) = (2x + 1)^5

Let f(x)=(2x+1)5\displaystyle f(x) = (2x + 1)^5. Find f′(0)\displaystyle f'(0).

Differentiate the outside power first, then multiply by the inside's derivative: f'(x) = 5(2x+1)⁴·2 = 10(2x+1)⁴. Plugging in x = 0 gives f'(0) = 10(1)⁴ = 10.

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