silemus.

12Derivative of ln⁡(x2+1)\ln(x^2 + 1)

Let f(x)=ln⁡(x2+1)\displaystyle f(x) = \ln(x^2 + 1). Find f′(1)\displaystyle f'(1).

Use the chain rule on ln(x²+1): the derivative is 2x/(x²+1). Plugging in x = 1 gives 2/2 = 1, so f'(1) = 1.

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