silemus.

8Limit of xe−xx e^{-x}

Find lim⁡x→∞xe−x\displaystyle \lim_{x\to\infty} x e^{-x}.

This is an ∞·0 form, so rewrite xe^(−x) as x/eˣ and apply L'Hôpital's rule: differentiate top and bottom to get 1/eˣ, which goes to 1/∞ = 0. So the limit is 0, confirmed since 20/e²⁰ ≈ 4.1×10⁻⁸.

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