silemus.

2Limit by factoring

Evaluate lim⁡x→2x2−4x−2\displaystyle \lim_{x\to 2} \frac{x^2 - 4}{x - 2}.

Direct substitution gives 0/0, so factor the top as (x−2)(x+2) and cancel the (x−2) with the bottom. The limit becomes x+2 as x→2, which is 4. Checking near x=2.01 gives about 4.01, confirming it.

How good is this answer?