2Limit by factoring
Evaluate .
Direct substitution gives 0/0, so factor the top as (x−2)(x+2) and cancel the (x−2) with the bottom. The limit becomes x+2 as x→2, which is 4. Checking near x=2.01 gives about 4.01, confirming it.
Evaluate .
Direct substitution gives 0/0, so factor the top as (x−2)(x+2) and cancel the (x−2) with the bottom. The limit becomes x+2 as x→2, which is 4. Checking near x=2.01 gives about 4.01, confirming it.