silemus.

1Limit of sin⁡(3x)/x\sin(3x)/x

Find lim⁡x→0sin⁡3xx\displaystyle \lim_{x\to 0} \frac{\sin 3x}{x}.

Rewrite sin(3x)/x as 3·sin(3x)/(3x), then substitute u = 3x so it becomes the standard limit sin(u)/u → 1. The answer is 3. Check: at x = 0.01, sin(0.03)/0.01 ≈ 3.00.

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