11Elimination, 2 equations
Solve the system by elimination: 4x + 3y = 10 and 2x − 3y = 14.
The solution is x = 4, y = −2. Adding the two equations cancels the y terms (3y and −3y), giving 6x = 24, so x = 4; substituting back into 4x + 3y = 10 gives y = −2. Check: 2(4) − 3(−2) = 8 + 6 = 14 ✓.