silemus.

10Solving a system by substitution

Solve the system by substitution: y = 2x − 1 and 3x + 2y = 12.

The lines meet at x = 2, y = 3. Substituting y = 2x − 1 into 3x + 2y = 12 gives 7x − 2 = 12, so x = 2, then y = 2(2) − 1 = 3. Check: 3(2) + 2(3) = 12 ✓.

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