52Bayes with a probability tree
A test for a disease is 95% sensitive and 90% specific. 1% of the population has the disease. A person tests positive. Find .
The tree splits first on disease (1%/99%), then each branch splits on test result using sensitivity/specificity. Multiplying along branches gives P(Disease∩+)=0.0095 and P(No disease∩+)=0.099; dividing the first by their sum gives P(Disease|+) ≈ 0.0876, about 8.8%.