silemus.

15Choosing 2 women, 1 man

A committee of 3 is chosen from 5 men and 4 women. In how many ways can it have exactly 2 women?

Pick 2 women from 4 and 1 man from 5, then multiply since both choices happen together: C(4,2)·C(5,1) = 6·5 = 30 ways.

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