silemus.

4Exactly 2 heads in 3 tosses

A fair coin is tossed 3 times. Find P(exactly 2 heads)\displaystyle P(\text{exactly 2 heads}).

There are 8 equally likely outcomes from 3 coin tosses, and 3 of them (HHT, HTH, THH) have exactly 2 heads. So P(exactly 2 heads) = 3/8. Checked with the binomial formula: C(3,2)(1/2)³ = 3/8.

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