silemus.

32Cross product of 3D vectors

Compute (2,3,4)×(5,6,7)\displaystyle (2, 3, 4) \times (5, 6, 7).

The cross product uses the determinant pattern with i, j, k: (-3, 6, -3). Each component comes from a 2×2 piece of the remaining rows, with the j term sign-flipped. Check: (-3,6,-3)·(2,3,4) = -6+18-12 = 0, confirming it's perpendicular.

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