silemus.

24Rank of a 3×33\times 3 matrix

Find the rank of A=[102013115]\displaystyle A = \begin{bmatrix}1 & 0 & 2\\0 & 1 & 3\\1 & 1 & 5\end{bmatrix}.

Row reduce A: R3 − R1 then R3 − R2 turns row 3 into all zeros, leaving two pivot rows. So rank(A) = 2. Check: row 3 of the original, (1,1,5), equals row1+row2, confirming it was dependent.

How good is this answer?