15Inverse of lower triangular
Let . Find the entry in row 3, column 1 of .
The (3,1) entry of A⁻¹ is the third coordinate of the solution to Ax = (1,0,0). Solving forward using A's rows gives x1=1, x2=−2, x3=5, so the entry you want is 5. Check: 3(1)+4(−2)+5 = 0 ✓.